IB MYP Chemistry · Year 4–5 · eAssessment topics All courses

MYP Chemistry · Topic 2

IUPAC naming and classification

A systematic name is a set of instructions. Read the stem for the chain, the ending for the family, and the number for the position.

AlkanesAlkenesAlcoholsCarboxylic acidsEstersStructural formulas
Curriculum scope

Topic: International Union of Pure and Applied Chemistry (IUPAC naming and classification of: alkanes, alkenes, alcohols, carboxylic acids and esters; structural formulas). The chapter covers why carbon forms so many compounds, how organic molecules are represented, the IUPAC rules for naming the five families up to six carbon atoms, and how to classify a molecule from its functional group.

Prior knowledge: carbon is in group 14 and has four outer electrons (Topic 1); a covalent bond is a shared pair of electrons (Topic 6).

Learning objectives

Objectives and contextOverview

By the end of this chapter you should be able to:

  • identify the functional group in a molecule and classify it as an alkane, alkene, alcohol, carboxylic acid or ester A
  • state the IUPAC name of a molecule with up to six carbon atoms in its main chain, including position numbers where needed A
  • draw the full structural (displayed) formula of a molecule from its name, showing every bond A
  • deduce molecular formulas using general formulas and the conservation of atoms A
  • relate the properties and uses of fuels, plastics, solvents and flavourings to the families they belong to D

In the seventeenth century a naturalist distilled a sharp-smelling acidic liquid from crushed ants and called it formic acid, from the Latin word for ant. Names like this record where a substance was first found, but they say nothing about its structure. Today more than ten million carbon compounds are known, and chemists need a naming system that works in the opposite direction: from the name you should be able to draw the molecule, and from the molecule you should be able to write the name. The International Union of Pure and Applied Chemistry (IUPAC) provides that system. Formic acid is methanoic acid: “meth-” says the molecule has one carbon atom, and “-oic acid” says it contains the carboxylic acid group.

02 / Why carbon

Carbon, chains and familiesClassification

Carbon has four electrons in its outer shell. It completes its outer shell by forming four covalent bonds, sharing one electron pair in each. Two features make carbon unusual. First, carbon atoms bond strongly to each other, so they can form chains of almost any length, branched chains and rings. Second, the same carbon skeleton can carry different groups of atoms — hydrogen, oxygen, nitrogen, halogens — so the variety of possible molecules is enormous. Compounds built on carbon skeletons are called organic compounds; simple carbon compounds such as carbon dioxide and carbonates are normally treated as inorganic.

A hydrocarbon is a compound of carbon and hydrogen only. Alkanes and alkenes are hydrocarbons. Alcohols, carboxylic acids and esters also contain oxygen, so they are not hydrocarbons, even though their skeletons are hydrocarbon chains.

Key definitions

Functional group: the atom or group of atoms that gives a family of compounds its characteristic reactions.
Homologous series: a family of compounds with the same functional group and the same general formula, in which each member differs from the next by a CH2 unit. Members have similar chemical properties and show a gradual trend in physical properties such as boiling point.

Table 2.1 The five families in this topic
FamilyFunctional groupHow to recognise itGeneral formulaName ending
Alkanenone — only C–C and C–H single bondshydrocarbon, all single bonds (saturated)CnH2n+2-ane
AlkeneC=C double bondhydrocarbon with one C=C (unsaturated)CnH2n-ene
Alcohol–OH (hydroxyl)O–H attached to a carbon that has only single bondsCnH2n+1OH-ol
Carboxylic acid–COOH (carboxyl)a carbon with C=O and O–H on the same carbonCnH2n+1COOH-oic acid
Ester–COO– (ester link)a carbon with C=O and an O that leads on to another carbonCnH2nO2-yl …-oate

The family decides the chemistry. Every alkane burns and is otherwise fairly unreactive; every alkene reacts by adding atoms across its double bond; every alcohol has an –OH group that makes the small ones mix with water; every carboxylic acid is a weak acid; every ester has a characteristic, often fruity, smell. Learning five families is far easier than learning ten million compounds.

Saturated and unsaturated

A saturated molecule has only single carbon–carbon bonds: each carbon carries as many hydrogen atoms as it can. An unsaturated molecule contains at least one C=C double bond. The words describe bonding, not solutions — do not confuse them with a saturated solution (Topic 5).

03 / Representing molecules

Formulas that show structureStructural formulas

Different formulas give different amounts of information. For ethanol:

  • the molecular formula, C2H6O, gives only the number of atoms of each element;
  • the condensed structural formula, CH3CH2OH, lists the atoms carbon by carbon, so the order of attachment can be read;
  • the full structural formula (also called the displayed formula) shows every atom and every bond as a line.
CCCCHHHHHHHHHHbutaneCCOHHHHHHethanol
Figure 2.1 Full structural formulas of butane (an alkane) and ethanol (an alcohol). Every carbon has exactly four bonds; every hydrogen has one; the oxygen in ethanol has two.

A full structural formula is the one to use whenever a question says “showing all of the bonds”. It is also the best way to check your own work, because each atom must have its correct number of bonds: C four, O two, H one. If a carbon in your drawing has three or five lines, the drawing is wrong.

Worked example 2.1 — from molecular to displayed formula

Given: propene, C3H6. Find: its full structural formula.
Reasoning: “prop-” → three carbons in a chain; “-ene” → one C=C. Put the double bond between carbons 1 and 2. Count bonds: carbon 1 already has two bonds to carbon 2, so it needs two hydrogens; carbon 2 has two bonds to carbon 1 and one to carbon 3, so it needs one hydrogen; carbon 3 has one bond to carbon 2, so it needs three hydrogens.
Check: 2 + 1 + 3 = 6 hydrogens, matching C3H6 and the general formula CnH2n.

CCHHHHetheneCCCHHHHHHpropene
Figure 2.2 Ethene and propene, the two simplest alkenes. The double line is the C=C double bond: two shared pairs of electrons between the same two carbon atoms.
Common trap: a formula with the wrong number of bonds

The most common error in drawn structures is a carbon with only three bonds, usually where a hydrogen has been forgotten at the end of a chain. Count the lines around every carbon before moving on.

04 / The naming system

How an IUPAC name is builtIUPAC naming

An IUPAC name for these families has up to three parts. The stem gives the number of carbon atoms in the longest chain that contains the functional group. The ending gives the family. A position number tells you which carbon carries the functional group, when there is more than one possibility.

Table 2.2 Stems for chain length
Carbon atoms123456
Stemmeth-eth-prop-but-pent-hex-
Alkanemethane CH4ethane C2H6propane C3H8butane C4H10pentane C5H12hexane C6H14

The rules for position numbers are the same for every family:

  1. Find the longest continuous chain of carbon atoms that contains the functional group.
  2. Number the chain from the end that gives the functional group the lowest possible number.
  3. Place the number immediately before the part of the name it refers to, separated by hyphens: but-1-ene, propan-2-ol.
  4. Leave the number out when there is only one possible position: ethene, propene, ethanol, methanoic acid. A carboxylic acid group is always on carbon 1, so it never needs a number.
Worked example 2.2 — choosing the lowest number

Given: CH3CH2CH=CH2. Find: its name.
Reasoning: four carbons → but-; C=C → -ene. Numbering from the left puts the double bond between carbons 3 and 4; numbering from the right puts it between carbons 1 and 2. The lower number is used, and the double bond is identified by the lower-numbered of its two carbons.
Answer: but-1-ene. “But-3-ene” describes the same molecule numbered from the wrong end and is not an accepted name.

Name builder

Choose a family, a chain length and a position. The model writes the IUPAC name, the molecular and condensed formulas, and draws the full structural formula by giving every carbon four bonds. If you choose a position that is not the lowest possible, it renumbers the chain and tells you why.

05 / Alkanes

AlkanesAlkanes

Alkanes are saturated hydrocarbons with the general formula CnH2n+2. They are the main compounds in natural gas (methane) and crude oil, and they are used as fuels: methane in gas cookers, propane and butane in bottled gas and portable heaters, and longer alkanes in petrol, diesel and candle wax. Because they contain only strong C–C and C–H single bonds, alkanes are unreactive except in combustion. With enough oxygen they burn completely to carbon dioxide and water:

C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(g)

The balancing follows directly from the formula: five carbons give 5CO2, twelve hydrogens give 6H2O, and the oxygen atoms on the right (10 + 6 = 16) fix 8O2 on the left. Topic 6 develops this method.

The general formula lets you identify an alkane from its molecular formula alone. Candle wax contains C25H52: 2 × 25 + 2 = 52, so it is an alkane. C5H12 fits the same pattern (2 × 5 + 2 = 12), so it belongs to the same family and is called pentane.

As the chain gets longer, the molecules are larger and the forces between them are stronger, so boiling points rise steadily along the series. Methane to butane are gases at room temperature, pentane to about C16 are liquids, and the long-chain alkanes in wax are solids. This gradual trend is what makes fractional distillation of crude oil possible (Topic 5).

Beyond this course

Longer alkanes can have branched chains, named by adding the branch in front of the main chain (for example methylpropane). Straight chains are sufficient for the examination tasks in this topic.

06 / Alkenes

AlkenesAlkenes

Alkenes are unsaturated hydrocarbons containing one C=C double bond. Their general formula is CnH2n: each has two hydrogen atoms fewer than the alkane with the same number of carbons, because two electrons from those carbon atoms are now used in the second bond between them. The smallest alkene has two carbon atoms (ethene, C2H4) — a double bond needs two carbons, so there is no “methene”.

The double bond is the functional group, and it is the reactive part of the molecule. Atoms can add across it, turning C=C into C–C. This is why alkenes are the starting materials for many plastics: thousands of ethene molecules join together to form poly(ethene), and propene molecules join to form poly(propene).

Alkenes are made from long-chain alkanes by cracking: the large molecules are heated, often with a catalyst, and break into smaller alkanes and alkenes. Atoms are conserved, so a missing product can be deduced by subtraction:

C10H22 → C2H4 + C3H6 + C5H12

Carbon: 10 − 2 − 3 = 5. Hydrogen: 22 − 4 − 6 = 12. The product C5H12 fits CnH2n+2, so it is an alkane (pentane). Cracking always produces at least one alkene, because there are not enough hydrogen atoms for every product to be saturated.

Exam language — “deduce the molecular formula”

When a question asks for the molecular formula, give the formula (C5H12, or a condensed version such as CH3(CH2)3CH3). The name pentane does not answer that question and was not credited.

07 / Alcohols

AlcoholsAlcohols

An alcohol contains the hydroxyl group, –OH, bonded to a carbon atom that has only single bonds. The name ending is “-ol”, added to the alkane stem after removing the final “e”: methane → methanol, ethane → ethanol. From three carbons upwards the –OH can be on different carbons, so a number is needed: propan-1-ol has the –OH on an end carbon, propan-2-ol on the middle carbon.

CCCOHHHHHHHHpropan-1-olCCCHHHOHHHHHpropan-2-ol
Figure 2.3 Propan-1-ol and propan-2-ol have the same molecular formula, C3H8O, but the –OH group is on a different carbon. They are different compounds with different boiling points.

The –OH group changes the properties considerably compared with the alkane of similar size. The small alcohols mix completely with water, and they have much higher boiling points than alkanes of similar mass, because the –OH groups attract neighbouring molecules strongly. Ethanol is a fuel (it burns to carbon dioxide and water, as alkanes do), a solvent in perfumes and medicines, and the alcohol in drinks. Methanol is a fuel and industrial solvent but is toxic.

Common trap: –OH is not hydroxide

The –OH in an alcohol is covalently bonded to carbon. It is not a hydroxide ion, OH−, and alcohols are not alkalis: ethanol solution is neutral. Write “hydroxyl group”, not “hydroxide”.

08 / Carboxylic acids

Carboxylic acidsCarboxylic acids

A carboxylic acid contains the carboxyl group, –COOH: a carbon atom that carries both a double-bonded oxygen (C=O) and an –OH group. The carbon of the –COOH group is counted as part of the chain, and it is always carbon 1. The name ending is “-oic acid”: methanoic acid, HCOOH (one carbon); ethanoic acid, CH3COOH (two carbons, the acid in vinegar); propanoic acid, CH3CH2COOH.

COHOHmethanoic acidCCHHHOOHethanoic acid
Figure 2.4 Methanoic acid and ethanoic acid. The carboxyl carbon has one C=O double bond and one C–O single bond, which leads to the acidic hydrogen.

Carboxylic acids are weak acids. In water only a small fraction of the molecules release the hydrogen of the –OH group as a hydrogen ion, and the process is reversible:

HCOOH(aq) ⇌ H+(aq) + HCOO−(aq)

They show the typical reactions of acids — with bases, carbonates and reactive metals — and they are neutralised by adding a base or an alkali (Topic 7).

Common trap: counting the carbons

CH3COOH has two carbon atoms, so it is ethanoic acid, not methanoic acid. The carbon in –COOH is part of the chain.

09 / Esters

EstersEsters

Esters form when a carboxylic acid reacts with an alcohol, usually with a little concentrated sulfuric acid as a catalyst. Water is also produced, and the reaction is reversible:

CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
ethanoic acid + ethanol ⇌ ethyl ethanoate + water

The ester link, –COO–, joins the two parts: the C=O comes from the acid and the single-bonded O leads on to the carbon chain that came from the alcohol.

CCHHHOOCHHCHHHethyl ethanoateCOHOCHHHmethyl methanoate
Figure 2.5 Ethyl ethanoate and methyl methanoate. The left-hand part (containing C=O) comes from the acid; the part to the right of the single-bonded oxygen comes from the alcohol.

An ester's name has two words, and the order catches many students out. The first word comes from the alcohol and ends in “-yl” (methyl, ethyl, propyl). The second word comes from the acid and ends in “-oate” (methanoate, ethanoate). So ethanol + propanoic acid gives ethyl propanoate, CH3CH2COOCH2CH3.

Esters are volatile liquids with sweet, fruity smells. Many natural flavours and scents are esters or mixtures containing them, and ethyl ethanoate is a common solvent in glues and nail-varnish remover. Some fabrics are made of polyesters, long molecules held together by many ester links.

Think like a chemist — reading an unfamiliar formula

Find the carbon that has the C=O. If it also has an –OH, the compound is a carboxylic acid. If its single-bonded oxygen leads to another carbon, it is an ester. If there is an –OH but no C=O on that carbon, it is an alcohol. If there is no oxygen at all, check for C=C (alkene) or only single bonds (alkane).

Classify the molecule

Each formula belongs to exactly one family. Choose it, then read the reason.

10 / Practice

Examination practicePast examination tasks

These tasks are adapted from past on-screen examinations; the chemistry, data and marks are unchanged. Attempt each one before opening the marking guidance.

A Criterion A · Knowing and understanding

Exam practice 2.1A4 marksDraw · Identify

Portable heaters need a fuel that is light and burns without much smoke. Butane and ethanol are both used.

(a) Draw the full structural formulas of butane and ethanol, showing all of the bonds. [2]
(b) Identify the class of organic compound to which each belongs. [2]
Marking guidance

(a) One mark for each correct full structural formula with every bond shown:

CCCCHHHHHHHHHHbutaneCCOHHHHHHethanol

(b) Butane: alkane (hydrocarbon also accepted). Ethanol: alcohol (alkanol also accepted).

Why: butane is C4H10, which fits CnH2n+2; ethanol has an –OH on a carbon with only single bonds. Check each carbon has four bonds — the end hydrogens are the ones most often forgotten.

Exam practice 2.2A1 markState

Formic acid, HCOOH, was first obtained by distilling a liquid collected from ants. It is the simplest carboxylic acid. State the systematic name for formic acid.

Marking guidance

Methanoic acid (“methanoic” alone was accepted).

Why: one carbon atom → meth-; carboxyl group → -oic acid. The carbon of –COOH is the only carbon.

Exam practice 2.3A2 marksState

Candle wax is composed of hydrocarbons with the formula C25H52. Another hydrocarbon in the same class is C5H12. State the name of C5H12 and its chemical class, choosing the class from: ester, alkane, alkene, carboxylic acid.

Marking guidance

Name: pentane. Class: alkane.

  • If the name was given as pentene, “alkene” was credited as a consistent follow-through for the class mark.

Why: both formulas fit CnH2n+2 (2 × 25 + 2 = 52; 2 × 5 + 2 = 12), and the class contains no oxygen, so ester and carboxylic acid are ruled out immediately.

Exam practice 2.4A4 marksSelect · State · Deduce

Plastics have very large molecules. Two common plastics are made from the organic compounds A and B shown below.

CCHHHHACCCHHHHHHB
(a) Select the chemical classification of molecules A and B: alkane, alkene, alcohol, carboxylic acid. [1]
(b) State the name of each chemical. [2]
(c) A and B can be obtained by breaking down long-chain molecules such as decane: C10H22 → C2H4 + C3H6 + X. Deduce the molecular formula of the missing product X. [1]
Marking guidance

(a) Alkene. (b) A: ethene. B: propene. (c) C5H12; CH3(CH2)3CH3 also accepted. The name “pentane” was not accepted, because a molecular formula was asked for.

Why: both molecules contain C=C. For (c), carbon 10 − 2 − 3 = 5 and hydrogen 22 − 4 − 6 = 12.

B Criterion B · Inquiring and designing

None of the available examination tasks assessed criterion B through this topic.

C Criterion C · Processing and evaluating

None of the available examination tasks assessed criterion C through this topic.

D Criterion D · Reflecting on the impacts of science

Exam practice 2.5D14 marksDiscuss

Discuss and evaluate the benefits of capturing the methane emitted by cows. In your answer, you should include:

  • the advantages and disadvantages of intensive cattle farming
  • the economic impacts of intensive cattle farming
  • the environmental advantages and disadvantages of using methane collected from cows as a source of

energy

  • the ethical aspects of using methane collected from cows as a source of energy
  • a concluding appraisal.
Marking guidance

A levelled response marked 1–4 in each strand:

StrandTop level requires
Advantages and disadvantages of cattle farmingAn advantage and a disadvantage, at least one justified
Economic impacts of cattle farmingMore than one economic impact
Environmental impact of methane captureMore than one environmental impact
Ethical aspects of methane captureA statement about the impact on a cow, with justification, linked to a statement about the methane hazard
Concluding appraisalA conclusion is given

See the criterion D guide for how discussion and evaluation answers are levelled.

Retrieval: names and formulas

Original practice questions for retrieval — not past examination items.

11 / Examination feedback

Examiner's overall observationEvidence from examination feedback

Examiner's overall observation

Performance on organic chemistry has varied between sessions. In one session, identifying organic molecules and their functional groups was listed among the areas students found most difficult: many could not classify a molecule by recognising its functional group. In a later session, identifying functional groups was among the areas where students were well prepared, and most students could select the correct diagram of an alcohol. A persistent weakness is applying family names too quickly: given methane and silane, many students assumed both were alkanes, although silane contains no carbon. The lesson is to classify from the actual atoms and bonds in front of you — find the functional group, check which elements are present — rather than from how a formula looks.

12 / Summary

Summary and knowledge organiserRevision

Essential knowledge

  • Carbon forms four covalent bonds and makes chains, so it forms a huge number of compounds, organised into homologous series by functional group.
  • Alkanes CnH2n+2 (saturated, -ane); alkenes CnH2n (C=C, -ene); alcohols –OH (-ol); carboxylic acids –COOH (-oic acid); esters –COO– (-yl …-oate).
  • Name = stem (chain length) + ending (family) + position number (lowest possible, only when needed).
  • Full structural formula: every bond drawn; C four bonds, O two, H one.
  • Ester names: alcohol part first (-yl), acid part second (-oate).

Stems

  • 1 meth · 2 eth · 3 prop
  • 4 but · 5 pent · 6 hex

Families

  • Alkane — only single bonds
  • Alkene — C=C
  • Alcohol — C–OH
  • Carboxylic acid — C(=O)OH
  • Ester — C(=O)O–C

Equations

  • C5H12 + 8O2 → 5CO2 + 6H2O
  • C10H22 → C2H4 + C3H6 + C5H12
  • acid + alcohol ⇌ ester + water

Must-remember distinctions

  • Hydroxyl group (–OH) ≠ hydroxide ion (OH−)
  • Hydrocarbon = C and H only
  • Saturated bonds ≠ saturated solution
  • Formula asked → give a formula, not a name

Examination checklist

  • Count bonds on every atom you draw
  • Count the –COOH carbon in the chain
  • Use the lowest position number
  • Classify from atoms present, not appearance

Other chapters: Criteria A–D · 1 · Periodic table · 2 · IUPAC naming · 3 · Atmosphere · 4 · Matter · 5 · Pure and impure · 6 · Bonding · 7 · Types of reaction

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