What this chapter covers20
Almost every plastic you handle in a day is made by one reaction repeated thousands of times. An alkene's C=C opens, and the two carbons it held link to the next alkene, and the next, until a chain thousands of atoms long has formed. Nothing else is made. That single idea covers how the polymer forms, how to draw it, how to work backwards from it to the monomer, and why the finished material is so hard to get rid of.
What topic 20 asks you to do
20.1 Addition polymerisation — the whole of topic 20 at AS Level
20.1.1 describe addition polymerisation as exemplified by poly(ethene) and
poly(chloroethene), PVC
20.1.2 deduce the repeat unit of an addition polymer obtained from a given monomer
20.1.3 identify the monomer(s) present in a given section of an addition polymer molecule
20.1.4 recognise the difficulty of the disposal of poly(alkene)s, i.e. non-biodegradability and harmful
combustion products
The verbs set the depth. 20.1.1 says describe: say what joins to what, what happens to the double bond, and write the equation for the two named polymers. 20.1.2 and 20.1.3 say deduce and identify, which is where the marks are. The two named examples are only the start: a question can give you any monomer, however unfamiliar, and expect its repeat unit, or give you a section of any chain and expect the monomers. The method is the same every time, so learn the method rather than a list of polymers. 20.1.4 says recognise: know the two problems — the polymers do not biodegrade, and burning them makes harmful products — and be able to say why.
What this page covers, and what it leaves out
This page is AS topic 20, which has one sub-topic, 20.1 Addition polymerisation. The A Level unit with the same name, topic 35 Polymerisation — condensation polymers, polyesters and polyamides, and proteins — is not covered. Nor is the free-radical mechanism of the reaction, or the industrial conditions for making poly(ethene): both appear briefly, marked as background, because they help the chemistry make sense, but neither is asked for. Addition polymerisation first appears in topic 14 as a reaction of alkenes (14.2.2(d)); this page takes it from there.
The page is in three parts. The first describes the reaction, using poly(ethene) and PVC and then the other common addition polymers. The second is the working core of the topic: drawing a repeat unit from any monomer, writing and balancing the equation, naming the polymer, handling copolymers, and reading monomers back out of a section of chain. The third deals with what happens to these polymers once they have been used.
Monomers, polymers and repeat units20.1.1
A polymer is a very large molecule made by joining together many small molecules. Each small molecule is a monomer. A typical poly(ethene) chain is built from between a few thousand and a few hundred thousand ethene molecules, so its relative molecular mass runs into the hundreds of thousands or more.
Definitions
Monomer — a small molecule that can join with many others like it to form a polymer.
Polymer — a long-chain molecule made by joining many monomer molecules together.
Addition polymerisation — the joining of many monomer molecules that contain a C=C double bond, to form
a polymer as the only product.
Repeat unit — the smallest part of the polymer chain that, repeated over and over, makes up the whole
chain.
Two words in the addition-polymerisation definition carry the marks. Unsaturated: the monomer must have a carbon–carbon double bond, because that is the bond that opens to make the chain. And only product: all the atoms of every monomer end up in the polymer. Nothing is given off, which is what separates addition polymerisation from the condensation polymerisation you meet at A Level, where a small molecule such as water is lost at every link.
| Feature | Addition polymerisation (this page) | Condensation polymerisation (A Level, topic 35) |
|---|---|---|
| group the monomer must have | C=C | two reactive groups, such as –COOH with –OH or –NH2 |
| products | the polymer only | the polymer and a small molecule such as H2O or HCl |
| formula of repeat unit compared with monomer | identical | monomers minus the small molecule |
| the polymer's backbone | carbon atoms only | contains the linking atoms, such as O or N |
| examples | poly(ethene), PVC, poly(propene) | polyesters, nylons, proteins |
The third row is worth holding on to. Because nothing is lost, the repeat unit of an addition polymer has exactly the same molecular formula as its monomer. Chloroethene is C2H3Cl, and so is the repeat unit of PVC. That is the quickest check on any repeat unit you draw: count the atoms, and they must match the monomer's.
The fourth row follows from the same idea. Only the two carbons of the C=C join the chain. Everything else on the monomer — a methyl group, a chlorine atom, a benzene ring, an ester group — ends up hanging off the chain as a side group. The backbone of every addition polymer is a string of carbon atoms and nothing else.
How to think about it
Picture every monomer as the same two-carbon clip, C=C, with different things fastened to its four corners. Polymerisation opens every clip and snaps them end to end. The clips form the chain; whatever was fastened to them comes along for the ride. Once you see monomers this way, poly(propene), PVC, polystyrene and PTFE are all the same polymer with different decorations.
Poly(ethene)20.1.1
Ethene, CH2=CH2, is the simplest alkene and the simplest monomer. When it polymerises, the double bond in each molecule opens and the molecules link into a chain of CH2 groups:
Written in condensed form:
nCH2=CH2 → –[CH2–CH2]n–
Three details in that drawing are what examiners look for, and each is easy to lose:
- the C=C in the monomer has become C–C in the polymer — a repeat unit drawn with a double bond is wrong;
- the bonds at the two ends of the repeat unit extend through the brackets, showing that the chain carries on in both directions;
- n appears twice: in front of the monomer and after the bracket. The same n on both sides is what makes the equation balance.
Common trap
Wrong: drawing the repeat unit of poly(ethene) as –CH2– on its own, because the chain is "just CH2 groups". Right: the repeat unit comes from one monomer molecule, so it has two carbons: –CH2–CH2–. Its formula, C2H4, matches ethene, as every addition repeat unit must match its monomer.
Two kinds of poly(ethene)
Poly(ethene) is made in two main forms. They are the same polymer — chains of CH2 groups — but made under different conditions, so the chains have different shapes and the materials behave differently.
| Low-density poly(ethene), LDPE | High-density poly(ethene), HDPE | |
|---|---|---|
| chains | many short branches | very few branches |
| packing | loose | close |
| density / g cm−3 | about 0.92 | about 0.95–0.96 |
| properties | soft, flexible, softens at a lower temperature | stiffer and stronger, softens at a higher temperature |
| uses | carrier bags, cling film, squeezy bottles | crates, bottles for milk and detergent, pipes |
The difference comes down to intermolecular forces (topic 3.6). The only forces between poly(ethene) chains are instantaneous dipole–induced dipole forces. They act over a short range, so they are much stronger when the chains lie close together along their length. Unbranched HDPE chains can do that; the branches on LDPE keep its chains apart.
Background, not required: how the two forms are made
LDPE is made at very high pressure (roughly 1000–3000 atm) and about 200 °C, with a trace of oxygen or an organic peroxide to start the reaction. The reaction runs by a free-radical mechanism, and radicals on the growing chain can pull hydrogen atoms off chains nearby, which starts branches. HDPE is made at low temperature (about 60 °C) and a few atmospheres, using a Ziegler–Natta catalyst, which adds each ethene to the chain in a controlled way and gives almost no branches. You are not asked for either set of conditions in 20.1; the hydrocarbons page lists them among the alkene reactions of 14.2.2.
Poly(chloroethene), PVC20.1.1
The second polymer the syllabus names is poly(chloroethene). Its monomer, chloroethene, CH2=CHCl, is ethene with one hydrogen replaced by chlorine. Its older name is vinyl chloride — CH2=CH– is the "vinyl" group — which is why the polymer is still called PVC, polyvinyl chloride.
nCH2=CHCl → –[CH2–CHCl]n–
Compare the two equations. Everything that happened to ethene happens to chloroethene: the double bond opens, the two carbons join the chain, and nothing is lost. The only difference is what hangs off the chain. That is the whole of 20.1.1 — once poly(ethene) makes sense, PVC is the same reaction with a chlorine atom in place of one hydrogen.
Exam alert
The monomer is chloroethene, not chloroethane. Chloroethane, CH3CH2Cl, has no C=C and cannot form an addition polymer at all. The polymer is named after the monomer, so it is poly(chloroethene) — "ene", even though the finished chain has no double bonds left in it.
Rigid and flexible PVC
Pure PVC is rigid. The C–Cl bonds are polar, so as well as instantaneous dipole–induced dipole forces there are permanent dipole–permanent dipole attractions between the chains, and they hold the chains firmly in place. Rigid PVC is used for window frames, drainpipes, gutters and flooring.
Adding a plasticiser changes that. Plasticiser molecules are small and fit between the polymer chains, pushing them apart. The forces between the chains weaken, the chains can slide past one another, and the material becomes soft and flexible. Plasticised PVC is used for electrical cable insulation, hoses and synthetic leather.
Plasticiser
A small molecule added to a polymer that gets between the chains, weakening the forces between them and so making the polymer softer and more flexible.
What happens to the bonds20.1.1
A C=C double bond is one σ bond and one π bond (topic 13.3). The π bond is the weaker of the two, and its electrons lie above and below the plane of the molecule, where they are exposed. In addition polymerisation, it is the π bond that breaks. Its two electrons are shared out: one goes into a new σ bond on each side of the monomer, linking it to its neighbours in the chain. The σ bond between the two original carbons stays where it was.
Three things change for each monomer that joins:
| in the monomer | in the polymer | |
|---|---|---|
| bond between the two carbons | C=C, one σ + one π | C–C, one σ |
| hybridisation of each carbon | sp2 | sp3 |
| shape around each carbon | trigonal planar, 120° | tetrahedral, 109.5° |
The last row explains why a real polymer chain is not the straight line drawn on paper. Each backbone carbon is tetrahedral, so the chain zig-zags, and because the single bonds can rotate, a long chain coils and tangles. The straight drawing is a convention, like drawing a displayed formula flat.
A double bond has become two single bonds for every monomer that joins, so the reaction releases energy. Using CIE's average bond enthalpies, each ethene breaks one C=C and forms two C–C bonds (the one that replaces its double bond, and its new link to the next monomer):
ΔH ≈ E(C=C) − 2E(C–C) = 610 − 2(350) = −90 kJ per mole of ethene
Polymerisation is exothermic, and industrial reactors have to be cooled to keep the temperature under control.
Background, not required: the free-radical mechanism
The mechanism is not part of 20.1, but it connects to things you have met. LDPE is made by a free-radical chain reaction, like the free-radical substitution of alkanes (14.1.3). An initiator such as a peroxide splits to give a radical, R•. The radical adds to ethene, using one electron from the π bond, which leaves a new radical on the far carbon: R• + CH2=CH2 → R–CH2–CH2•. That radical adds to the next ethene, and so on — propagation, repeated thousands of times. Termination happens when two radicals meet and pair up.
Common addition polymers20.1.1
Poly(ethene) and PVC are the syllabus's two examples, but every alkene with something on its double bond gives a polymer by the same reaction. These are the ones you are most likely to be given, and they are worth recognising:
| Monomer | Monomer formula | Repeat unit | Polymer | Typical uses |
|---|---|---|---|---|
| ethene | CH2=CH2 | –CH2–CH2– | poly(ethene) | bags, film, bottles, crates |
| propene | CH2=CHCH3 | –CH2–CH(CH3)– | poly(propene) | rope, carpet fibres, food containers |
| chloroethene | CH2=CHCl | –CH2–CHCl– | poly(chloroethene), PVC | window frames, pipes, cable insulation |
| phenylethene | CH2=CHC6H5 | –CH2–CH(C6H5)– | poly(phenylethene), polystyrene | cases, disposable cutlery; expanded for packaging and insulation |
| tetrafluoroethene | CF2=CF2 | –CF2–CF2– | poly(tetrafluoroethene), PTFE | non-stick coatings, low-friction bearings |
| propenenitrile | CH2=CHCN | –CH2–CH(CN)– | poly(propenenitrile) | acrylic fibres |
Read down the monomer column and every one is CH2=CH2 with one or more hydrogens swapped for something else. Read down the repeat-unit column and every one is –C–C– with the same things swapped. The older names follow the same pattern as PVC: phenylethene is styrene, propenenitrile is acrylonitrile.
How to think about it
The side group decides the properties. A methyl group makes poly(propene) stiffer than poly(ethene). A benzene ring is bulky, so polystyrene is rigid and brittle. Polar C–Cl bonds make PVC rigid until a plasticiser is added. In PTFE, the fluorine atoms form a tight sheath round a carbon backbone held by very strong C–F bonds, which is why almost nothing sticks to it or reacts with it.
Drawing the repeat unit from a monomer20.1.2
This is the skill 20.1.2 tests, and it works for any monomer, however unfamiliar. Three steps:
Monomer → repeat unit
1. Find the C=C. Redraw the monomer so the two carbons of the double bond sit side by side, with
everything else attached to them drawn above and below.
2. Change the C=C to C–C, and add a bond sticking out of each carbon sideways, to show the chain
continuing.
3. Put square brackets round the two carbons and their groups, with the side bonds passing through the
brackets, and write n after the closing bracket.
Step 1 is where most of the work is, because monomers are often printed in a way that hides the double bond. Propene is usually written CH3CH=CH2, which puts the methyl group in line with the double bond. Redrawn for step 1, the two carbons of the C=C become the chain and the CH3 goes above or below one of them. It does not matter which carbon you hang it on, or whether it goes up or down: all of these are the same repeat unit, and all score.
Worked example: ethenyl ethanoate
The monomer for PVA, the polymer in wood glue, is ethenyl ethanoate (vinyl acetate), CH3COOCH=CH2. It looks nothing like the examples above until you find the C=C.
Step 1. The only C=C is at the right-hand end: CH=CH2. The whole ester group,
CH3COO–, is attached to one carbon of it. So the monomer is CH2=CH–OCOCH3:
ethene with one hydrogen replaced by –OCOCH3.
Steps 2 and 3. Open the double bond; the ester group becomes a side group.
Check: the repeat unit is C4H6O2, the same as the monomer. The C=O inside the ester group is not touched — only a carbon–carbon double bond polymerises.
Build any repeat unit in the model below. It draws the equation from the monomer's structure, then a section of the chain, and counts the atoms to confirm nothing has been lost.
Common trap
Wrong: putting a side group into the backbone. For poly(propene), –CH2–CH2–CH2– treats the methyl carbon as part of the chain, which gives the right formula and the wrong polymer — that is a section of poly(ethene). Right: only the two carbons of the C=C are in the backbone. –CH2–CH(CH3)– has the methyl group hanging off it.
Exam alert: how many repeat units?
Read the question for what it asks. "Draw the repeat unit" wants one unit in brackets. "Draw a section of the polymer showing two repeat units" wants four backbone carbons with the continuation bonds at both ends — two monomers' worth. If you also bracket that section and put n after it, then the monomer coefficient in any equation has to be 2n (next section).
Writing the equation20.1.2
An equation for addition polymerisation balances in the same way as any other: the same number of each kind of atom on both sides. The only unusual thing is that the numbers are written with n in them.
nCH2=CHCH3 → –[CH2–CH(CH3)]n–
On the left, n propene molecules contain 3n carbon atoms. On the right, n repeat units, each with three carbons, also contain 3n. The equation balances.
If the bracket holds two monomer units, the coefficient has to change to match:
Worked example: checking a coefficient by counting carbons
A student writes nCH2=CHCH3 → –[CH2–CH(CH3)–CH2–CH(CH3)]n–.
Left: n × 3 = 3n carbons. Right: n × 6 = 6n carbons. Not balanced. The bracket holds two propene units, so the coefficient must be 2n: 2n × 3 = 6n.
The general rule: the coefficient of the monomer is the number of monomer units inside the bracket, times n. Try each choice below — the model counts the carbons on both sides so a wrong coefficient shows itself.
How to think about it
Counting carbons is enough to check an addition-polymer equation. Every monomer's whole formula ends up in the polymer, so if the carbons balance, every other element balances with them. That is not true of the condensation polymers at A Level, where water or HCl is lost and has to be counted separately.
Naming addition polymers20.1.2
An addition polymer is named by putting the name of its monomer in brackets after "poly":
| Monomer | Polymer | Other names you will see |
|---|---|---|
| ethene | poly(ethene) | polythene, polyethylene |
| propene | poly(propene) | polypropylene |
| chloroethene | poly(chloroethene) | polyvinyl chloride, PVC |
| phenylethene | poly(phenylethene) | polystyrene |
| tetrafluoroethene | poly(tetrafluoroethene) | PTFE |
| propenenitrile | poly(propenenitrile) | polyacrylonitrile |
The brackets matter when the monomer's name has more than one word or begins with a number — poly(1,1-dichloroethene), poly(methyl 2-methylpropenoate) — so it is simplest to use them every time.
Common trap
Wrong: poly(ethane), poly(propane), poly(chloroethane), reasoning that the chain has only single bonds. Right: the name records what the polymer was made from, and the monomer is an alkene. The polymer keeps "ene" in its name even though it has no double bonds left.
Monomers that look less like ethene20.1.2
Because a question can use any monomer, it helps to know which molecules can polymerise and how to handle the awkward ones.
The test: is there a C=C?
A molecule can form an addition polymer if it has a carbon–carbon double bond. Other multiple bonds do not count. Propanone has C=O and ethanenitrile has C≡N, and neither forms an addition polymer by this route. And the double bonds in a benzene ring are not really double bonds at all: the ring's π electrons are delocalised (you meet this at A Level), and benzene does not undergo addition polymerisation. Phenylethene polymerises only through the C=C outside its ring.
Groups on both carbons
When both carbons of the C=C carry a group, both groups end up on the chain — one on each backbone carbon. But-2-ene, CH3CH=CHCH3, gives a chain with a methyl group on every carbon:
nCH3CH=CHCH3 → –[CH(CH3)–CH(CH3)]n–
Two groups on one carbon
When both groups are on the same carbon, they stay together on the same backbone carbon. Methyl 2-methylpropenoate, CH2=C(CH3)COOCH3, is the monomer for Perspex:
The methyl group and the ester group are both on the second carbon. Moving one of them to the other carbon would describe a different monomer.
Exam alert
Monomers are often printed as condensed or skeletal formulae. Before drawing anything, find the C=C, then write down which groups are on its left-hand carbon and which are on its right-hand carbon. That list is the repeat unit — the rest is layout.
Copolymers20.1.2
A polymer made from a single monomer is a homopolymer. When two different monomers polymerise together, they form a copolymer, with both kinds of unit in the same chain. Ethene and ethenyl ethanoate copolymerise to give EVA, the soft, rubbery material in sports-shoe soles and hot-melt glue.
In a real copolymer the two kinds of unit are usually spread along the chain in no fixed order. For exam purposes, draw them alternating, one of each, and put the pair in the bracket:
The carbon count still checks it: n × 2 + n × 4 = 6n on the left, and n × 6 on the right. The builder model above makes any copolymer: choose a second monomer.
Why the syllabus wording still covers this
20.1.2 says "from a given monomer", but 20.1.3 says "monomer(s)", so a section of copolymer can appear in a question that asks you to work backwards. Being able to go forwards makes going backwards easier.
Finding the monomer from a section of polymer20.1.3
20.1.3 runs 20.1.2 backwards. You are given a section of a polymer chain — often long, often with unfamiliar side groups — and asked for the monomer or monomers that made it. The method is the reverse of the one in section 7:
Section of polymer → monomer(s)
1. Cut the backbone into pieces two carbons long. Every addition monomer contributed exactly two
backbone carbons, so every piece is one monomer.
2. In each piece, take off the bonds that went to the neighbouring pieces and put the double bond back
between the two carbons. Keep every side group on the carbon it was attached to.
3. List the different monomers you find. Most sections give one; a copolymer gives two.
Worked example: a copolymer
A section of chain reads –CH2–CH2–CF2–CF2–CH2–CH2–CF2–CF2–.
Step 1. Pieces: CH2–CH2 | CF2–CF2 | CH2–CH2 | CF2–CF2.
Step 2. Double bonds back in: CH2=CH2 and CF2=CF2.
Step 3. Two monomers: ethene and tetrafluoroethene. This copolymer, ETFE, is the material used for the
inflated roof panels of some stadiums.
Work through the sections in the model. Some start part-way through a monomer unit, some are copolymers, and one is a trap. Select every monomer you think was used, then check; "show the working" draws the cuts.
Common trap
Wrong: giving the saturated compound — "chloroethane" for PVC, "propane" for poly(propene) — because that is what the two-carbon piece looks like once cut out. Right: the piece had its double bond opened to join the chain, so the monomer must have the double bond back: chloroethene, propene. A monomer for an addition polymer always has a C=C.
Exam alert
Give the monomer as the question asks: a name, a structural formula such as CH2=CHCl, or a displayed formula. When a displayed formula is asked for, draw every bond, including the C=C, and every hydrogen. Check your answer by counting: the monomer's formula must match one repeat unit of the chain.
Where to make the first cut20.1.3
The printed section of chain does not always start at the beginning of a monomer unit. A section of PVC could be drawn as –CHCl–CH2–CHCl–CH2– just as well as –CH2–CHCl–CH2–CHCl–. For a homopolymer this never matters: cut it either way and every piece is CH2 joined to CHCl, which is chloroethene. The same is true of almost every copolymer you will be given.
There is one kind of section where the starting point does matter. Look at this chain:
Cut from the first carbon, the pieces are CH2–CH2 and CHCl–CHCl: a copolymer of ethene and 1,2-dichloroethene.
Cut from the second carbon, every piece is CH2–CHCl, some the right way round and some reversed: chloroethene alone, with some units joined head to head.
Both readings follow the rules, and the chain by itself cannot tell them apart. Real PVC is almost entirely head to tail, so the first reading is the likely intended answer, but a question that means to test this will show the repeat unit in brackets or tell you how many monomers were used. The model in the previous section tries both starting points on every chain and reports when they disagree; the last chain in its list is this one.
How to think about it
The two readings only differ when a monomer has groups on both of its carbons in a pattern that can be split another way. If every monomer in the chain has an unsubstituted CH2 end, the CH2 groups mark where each unit starts, and there is only one way to cut it.
Chain length and relative molecular mass20.1.2
Because nothing is lost when the monomers join, the relative molecular mass of a chain is simply the number of repeat units times the Mr of one of them. The two end groups, which depend on how the chain started and stopped, are too small to matter.
number of repeat units, n = Mr(polymer) ÷ Mr(repeat unit)
Worked example
A sample of PVC has an average Mr of 125 000. How many monomer molecules make up an average chain?
Mr(C2H3Cl) = 2(12.0) + 3(1.0) + 35.5 = 62.5
n = 125 000 ÷ 62.5 = 2000 chloroethene molecules per chain.
Two things are worth noticing. First, the Mr of a polymer sample is always an average: the chains in a sample stop growing at different lengths, so a polymer does not have one fixed Mr the way a simple compound does, and it softens over a range of temperatures rather than melting sharply. Second, the chains are extraordinarily long for their width, which is why they tangle, and why a polymer behaves so differently from its monomer.
Why poly(alkene)s are unreactive20.1.4
20.1.4 is about poly(alkene)s: addition polymers made from alkenes, such as poly(ethene) and poly(propene), and by extension the others on this page. Everything difficult about disposing of them comes from one property: they are chemically very unreactive. That is exactly why they are chosen for food wrapping, chemical bottles and water pipes — and exactly why they are so hard to get rid of afterwards.
The reason for the unreactivity is in the bonds that remain once the polymer has formed:
- There is no C=C left. The π bond was the reactive part of the monomer — the site of electrophilic addition in topic 14 — and every one of them was used up in making the chain. A poly(alkene) is, chemically, a very large alkane.
- The C–C and C–H bonds are almost non-polar. Carbon and hydrogen have similar electronegativities (2.55 and 2.20), so there is no δ+ carbon for a nucleophile such as water or hydroxide to attack, the way it attacks the carbon of a C–Br bond in a halogenoalkane (topic 15).
- The bonds are strong. C–C and C–H need 350 and 410 kJ mol−1 to break. In PTFE the C–F bond, which is polar, is also one of the strongest single bonds in organic chemistry.
The chart below places the bonds in poly(alkene)s against bonds you have seen react at AS. The reactive ones are either weaker (C–Br, C–I, the π part of C=C) or polar enough to give a clear δ+ carbon (the C–O of an ester, which is hydrolysed in topic 16). The polymer bonds sit in the corner that neither reagents nor enzymes can do much with.
How to think about it
Alkanes are unreactive, and a poly(alkene) is an alkane with a very long chain. Almost everything you know about alkanes (topic 14.1) transfers directly: they do not react with acids, alkalis, oxidising agents in solution or water, and the reactions they do undergo — combustion and free-radical substitution — need high temperatures or UV light.
Non-biodegradability20.1.4
Definitions
Biodegradable — able to be broken down by microorganisms, such as bacteria and fungi, into
simpler substances.
Non-biodegradable — not broken down by microorganisms, so it persists in the environment.
Microorganisms break materials down using enzymes, and enzymes work by attacking particular polar bonds — the C–O links in starch and cellulose, the C–N links in proteins. A poly(alkene) chain offers nothing of the kind: just C–C and C–H bonds, over and over. With no enzyme able to start on it, a poly(alkene) is non-biodegradable. It persists for decades, and probably much longer.
That has three consequences:
- Landfill. Buried poly(alkene)s stay essentially unchanged. Because they are also bulky and low-density, they take up a large volume of the space available.
- Litter. Discarded bags, bottles and packaging last for years in the environment. They entangle animals and are eaten by them, and plastic waste collects in rivers and oceans.
- Fragments. Sunlight and physical wear break large pieces into smaller ones without breaking the chains down to simple molecules, so the polymer ends up as tiny particles that are even harder to collect.
Common trap
Wrong: "poly(alkene)s are non-biodegradable because they are toxic to bacteria." Right: they are non-biodegradable because they are unreactive — the chains have no polar bonds or double bonds for the bacteria's enzymes to attack. The explanation the syllabus wants is about bonding, not toxicity.
What is being done about it
Biodegradable polymers do exist, but they are made differently: poly(lactic acid), for example, is a condensation polymer with ester links in its chain, which water and enzymes can attack. That places it in the A Level topic, not here. Some poly(alkene)s are made photodegradable by building in groups that absorb UV light and break the chain, but the fragments that result are still poly(alkene).
Burning: carbon dioxide, carbon monoxide and soot20.1.4
If a poly(alkene) cannot be left to rot, the obvious alternative is to burn it. Poly(alkene)s are hydrocarbons, so they burn well and release a lot of energy — incinerators can use that energy to generate electricity. But burning creates its own problems, and 20.1.4 names them as "harmful combustion products".
In plenty of oxygen, a hydrocarbon polymer burns completely to carbon dioxide and water. Per repeat unit of poly(ethene):
C2H4 + 3O2 → 2CO2 + 2H2O
or, for the whole chain, (C2H4)n + 3nO2 → 2nCO2 + 2nH2O. Even this "clean" case is not harmless: carbon dioxide is a greenhouse gas, and burning a polymer made from crude oil puts carbon that was underground into the atmosphere.
In a limited supply of oxygen — a bonfire, a house fire, a badly run incinerator — combustion is incomplete. Some of the carbon ends up as carbon monoxide, which is toxic because it binds to haemoglobin in the blood more strongly than oxygen does, and some as carbon: soot, fine particles that damage the lungs. These are the same products as the incomplete combustion of alkanes in topic 14.1.
The model below burns one repeat unit of each polymer with a chosen fraction of the oxygen it needs. It shows the balanced equation for complete combustion, and what comes out as the oxygen runs short.
Worked example: balancing a polymer combustion
Write an equation for the complete combustion of one repeat unit of poly(propene).
The repeat unit is C3H6. Carbon: 3CO2. Hydrogen: 3H2O. Oxygen needed: 6 + 3 = 9 atoms, which is 4½O2.
C3H6 + 4½O2 → 3CO2 + 3H2O or 2C3H6 + 9O2 → 6CO2 + 6H2O
Burning chlorinated polymers20.1.4
PVC adds a problem that poly(ethene) does not have: chlorine. When PVC burns, the chlorine leaves as hydrogen chloride, taking hydrogen from the chain:
2C2H3Cl + 5O2 → 4CO2 + 2H2O + 2HCl
Hydrogen chloride is a toxic, corrosive gas. It dissolves in water droplets in the air to give hydrochloric acid, which contributes to acid rain, and in a fire it is one of the main dangers to anyone breathing the smoke. Incinerators that burn waste containing PVC must remove it from their flue gases before release, by passing them through a scrubber containing a base that neutralises the acid.
Two more products form when chlorinated polymers burn at too low a temperature, or with too little oxygen:
- Phosgene, COCl2 — a highly poisonous gas, used as a chemical weapon in the First World War.
- Dioxins — a family of chlorinated organic compounds that are extremely toxic even in tiny amounts, and persist in the environment and in body fat.
To prevent them, incinerators burn waste at a high temperature, above about 850 °C, with plenty of oxygen, and clean their flue gases before release. An open fire or garden bonfire does none of these things, which is why burning PVC outside an incinerator is so dangerous.
| Product | From | When | Why it is harmful |
|---|---|---|---|
| carbon dioxide, CO2 | every polymer on this page | always | greenhouse gas |
| carbon monoxide, CO | every polymer on this page | limited oxygen | toxic: reduces the blood's ability to carry oxygen |
| soot, C | every polymer on this page | very limited oxygen | fine particles damage the lungs |
| hydrogen chloride, HCl | PVC and other chlorinated polymers | always | toxic, corrosive, acidic gas |
| phosgene and dioxins | PVC and other chlorinated polymers | low temperature, poor combustion | extremely toxic |
| hydrogen cyanide, HCN | nitrogen-containing polymers such as poly(propenenitrile) | limited oxygen | extremely toxic |
Exam alert
When asked for a harmful product of burning a particular polymer, match the product to the atoms in it. Poly(ethene) and poly(propene) contain only carbon and hydrogen, so HCl cannot be the answer for them. For PVC, HCl is the product examiners expect first.
PTFE
PTFE hardly burns at all, but strongly overheated PTFE — a non-stick pan left empty on a high flame — gives off fumes containing toxic fluorine compounds. The same C–F bonds that make it so unreactive make whatever does form from it hazardous.
Weighing the disposal options20.1.4
Every way of dealing with used poly(alkene)s has a drawback, and "recognise the difficulty" means being able to say what each one is.
| Option | Advantage | Difficulty |
|---|---|---|
| landfill | cheap and simple | non-biodegradable, so the waste stays; uses up land; nothing is recovered |
| incineration | reduces volume; the heat released can generate electricity | CO2; CO and soot if combustion is incomplete; HCl, phosgene and dioxins from PVC, so scrubbers and high temperatures are needed |
| mechanical recycling: sort, clean, melt, re-form | saves crude oil and energy | plastics must be collected and sorted by type; the polymer weakens each time it is reprocessed |
| feedstock recycling: crack back to small molecules | gives alkenes and fuels that can be used again | needs high temperatures and energy (like the cracking of alkanes, 14.1.4) |
Recycling depends on sorting because different polymers soften at different temperatures and do not mix well when melted together. That is why many plastic items carry a number from 1 to 7 inside a triangle, which identifies the polymer: 2 for HDPE, 3 for PVC, 4 for LDPE, 5 for poly(propene), 6 for polystyrene.
What to write for 20.1.4
Poly(alkene)s are unreactive — saturated, with non-polar C–C and C–H bonds — so they are non-biodegradable and persist in landfill and the environment. Burning them gives CO2, and with limited oxygen toxic CO and soot; chlorinated polymers such as PVC also give HCl, and at low temperatures phosgene and dioxins.
Self-test20.1
Twenty questions across all four outcomes. Each answer comes with the reason, so a wrong answer is worth reading as closely as a right one.
Definitions to learn20.1
| Term | Definition |
|---|---|
| monomer | a small molecule that can join with many others to form a polymer |
| polymer | a long-chain molecule made by joining many monomer molecules together |
| addition polymerisation | the joining of many monomer molecules containing a C=C double bond, to form a polymer as the only product |
| repeat unit | the smallest part of a polymer chain that, repeated, makes up the whole chain; for an addition polymer it has the same molecular formula as the monomer |
| poly(alkene) | an addition polymer made from an alkene monomer |
| homopolymer | a polymer made from one kind of monomer |
| copolymer | a polymer made from two or more different monomers |
| side group | an atom or group attached to the backbone of a polymer rather than part of it |
| plasticiser | a small molecule added to a polymer that gets between the chains, weakening the forces between them and making the polymer more flexible |
| biodegradable | able to be broken down by microorganisms into simpler substances |
| non-biodegradable | not broken down by microorganisms, so it persists in the environment |
| incomplete combustion | burning in a limited supply of oxygen, giving carbon monoxide and/or carbon as well as, or instead of, carbon dioxide |
The two methods, side by side
| Monomer → repeat unit (20.1.2) | Section of polymer → monomer(s) (20.1.3) |
|---|---|
| find the C=C; put its two carbons side by side, groups above and below | cut the backbone into two-carbon pieces |
| make C=C into C–C; add a continuation bond to each carbon | remove the bonds to the neighbouring pieces; put C=C back |
| bracket it; write n after; n × units in bracket in front of the monomer | list the different monomers; check each has a C=C |
Data used on this page20.1
The models compute everything they show from the monomer structures in the first table and the values in the second. The bond enthalpies are the average values CIE use, and the electronegativities are Pauling values; they are reference values, not the official data booklet, and other sources differ by a few units.
| Monomer | Structural formula | Formula | Mr | Polymer |
|---|---|---|---|---|
| ethene | CH2=CH2 | C2H4 | 28.0 | poly(ethene) |
| propene | CH2=CHCH3 | C3H6 | 42.0 | poly(propene) |
| chloroethene | CH2=CHCl | C2H3Cl | 62.5 | poly(chloroethene) |
| phenylethene | CH2=CHC6H5 | C8H8 | 104.0 | poly(phenylethene) |
| tetrafluoroethene | CF2=CF2 | C2F4 | 100.0 | poly(tetrafluoroethene) |
| propenenitrile | CH2=CHCN | C3H3N | 53.0 | poly(propenenitrile) |
| but-1-ene | CH2=CHC2H5 | C4H8 | 56.0 | poly(but-1-ene) |
| 2-methylpropene | CH2=C(CH3)2 | C4H8 | 56.0 | poly(2-methylpropene) |
| but-2-ene | CH3CH=CHCH3 | C4H8 | 56.0 | poly(but-2-ene) |
| 1,1-dichloroethene | CH2=CCl2 | C2H2Cl2 | 97.0 | poly(1,1-dichloroethene) |
| 1,2-dichloroethene | ClCH=CHCl | C2H2Cl2 | 97.0 | poly(1,2-dichloroethene) |
| fluoroethene | CH2=CHF | C2H3F | 46.0 | poly(fluoroethene) |
| ethenyl ethanoate | CH2=CHOCOCH3 | C4H6O2 | 86.0 | poly(ethenyl ethanoate) |
| methyl 2-methylpropenoate | CH2=C(CH3)COOCH3 | C5H8O2 | 100.0 | poly(methyl 2-methylpropenoate) |
| propenoic acid | CH2=CHCOOH | C3H4O2 | 72.0 | poly(propenoic acid) |
| propenamide | CH2=CHCONH2 | C3H5NO | 71.0 | poly(propenamide) |
| Bond | Bond enthalpy / kJ mol−1 | Electronegativity difference | Found in |
|---|---|---|---|
| C–C | 350 | 0.00 | poly(alkene)s |
| C–H | 410 | 0.35 | poly(alkene)s |
| C–Cl | 340 | 0.61 | poly(alkene)s |
| C–F | 485 | 1.43 | poly(alkene)s |
| C≡N | 890 | 0.49 | poly(alkene)s |
| C=C π | 260 | 0.00 | molecules that react at AS |
| C–Br | 280 | 0.41 | molecules that react at AS |
| C–I | 240 | 0.11 | molecules that react at AS |
| C–O | 360 | 0.89 | molecules that react at AS |
Relative atomic masses used: C 12.0, H 1.0, N 14.0, O 16.0, F 19.0, Cl 35.5. Electronegativities: H 2.20, C 2.55, N 3.04, O 3.44, F 3.98, Cl 3.16, Br 2.96, I 2.66. The chain-length model takes a C–C bond as 0.154 nm and the backbone angle as 109.5°.