What this chapter covers18.1, 18.2
Carboxylic acids contain the –COOH functional group: a carbonyl group with an –OH on the same carbon. The hydrogen on that –OH is acidic enough to react with metals, alkalis and carbonates. This page covers two related topics: 18.1 deals with the production and reactions of carboxylic acids, while 18.2 covers esters — the products of the condensation reaction between a carboxylic acid and an alcohol — and their hydrolysis.
What topics 18.1 and 18.2 ask you to do
18.1 Carboxylic acids
18.1.1 recall the reactions by which carboxylic acids can be
produced: (a) oxidation of primary alcohols and aldehydes with acidified
K2Cr2O7 or acidified KMnO4 and refluxing (b)
hydrolysis of nitriles with dilute acid or dilute alkali followed by acidification (c)
hydrolysis of esters with dilute acid or dilute alkali and heat followed by acidification
18.1.2 describe: (a) the redox reaction with reactive metals to produce a salt and
H2(g) (b) the neutralisation reaction with alkalis to produce a salt and
H2O(l) (c) the acid–base reaction with carbonates to produce a salt and
H2O(l) and CO2(g) (d) esterification with alcohols with concentrated
H2SO4 as catalyst (e) reduction by LiAlH4 to form a primary
alcohol
18.2 Esters
18.2.1(a) recall the condensation reaction between an alcohol and a
carboxylic acid with concentrated H2SO4 as catalyst to produce esters
18.2.2 describe the hydrolysis of esters by dilute acid and by dilute alkali and heat
The verbs tell you how much detail to give. 18.1.1 says recall: reagents, conditions and equations. 18.1.2 says describe: equations, reagents, conditions and observations. 18.2.1 says recall: the reaction, its reagents and conditions. 18.2.2 says describe: equations, reagents, conditions and the difference between acid hydrolysis and alkaline hydrolysis.
What this page covers, and what it leaves out
This page covers AS topics 18.1 (Carboxylic acids) and 18.2 (Esters). Topic 17.1 (Aldehydes and ketones) is in a separate chapter. The A Level topic 27 (Carboxylic acids and their derivatives, including acyl chlorides and acid anhydrides) is not covered here.
The page is in two parts. The first covers carboxylic acids and esters: how they are made, how carboxylic acids behave as acids, how esters are formed and hydrolysed. The second is a review section with a data summary and a self-test.
Carboxylic acids: the –COOH group18.1
A carboxylic acid contains the functional group –COOH: a carbonyl group, C=O, with an –OH attached to the same carbon. This combination gives the group its distinctive behaviour — the hydrogen on the –OH is acidic enough to be lost as H+ to water, metals, alkalis and carbonates.
Definition
A carboxylic acid has the functional group –COOH (the carboxyl group), which can also be written –CO2H.
Name a carboxylic acid from the longest chain that includes the –COOH carbon. Drop the –e of the parent alkane and add –oic acid. The –COOH is always C1, so no locant is needed.
| Name | Formula | Mr |
|---|---|---|
| methanoic acid | HCOOH | 46 |
| ethanoic acid | CH3COOH | 60 |
| propanoic acid | CH3CH2COOH | 74 |
| butanoic acid | CH3CH2CH2COOH | 88 |
Physical properties
Carboxylic acids have high boiling points — much higher than aldehydes or ketones of similar Mr. This is because the –COOH group can form two hydrogen bonds to another –COOH group at once, giving a cyclic dimer held by two O–H···O=C hydrogen bonds. In the liquid and in the vapour at temperatures just above the boiling point, most molecules exist as these dimers.
The short-chain acids are soluble in water (ethanoic acid mixes in all proportions). As the chain lengthens, the non-polar hydrocarbon tail dominates and solubility falls.
Making carboxylic acids18.1.1
The syllabus lists three routes to carboxylic acids. Two of them have already been met in earlier topics; the third is new here.
(a) Oxidation of primary alcohols and aldehydes
Heat a primary alcohol under reflux with excess acidified K2Cr2O7 or acidified KMnO4. The alcohol is oxidised first to the aldehyde and then to the carboxylic acid. Starting from the aldehyde itself, a single [O] step suffices.
CH3CH2OH + 2[O] → CH3COOH + H2O ethanol → ethanoic acid
CH3CHO + [O] → CH3COOH ethanal → ethanoic acid
Reflux, not distillation: the aldehyde must stay in contact with the oxidising agent. The colour change is orange (Cr2O72−) to green (Cr3+).
(b) Hydrolysis of nitriles
A nitrile, RCN, is hydrolysed by heating under reflux with dilute hydrochloric acid or with dilute sodium hydroxide followed by acidification. The –CN group is converted to –COOH (or –COO− with alkali, which must be acidified to release the free acid).
CH3CN + 2H2O + HCl → CH3COOH + NH4Cl (acid hydrolysis)
CH3CN + NaOH + H2O → CH3COO−Na+ + NH3 (alkaline hydrolysis, then acidify)
This is synthetically important because adding HCN to a carbonyl compound (17.1.2(b)) gives a hydroxynitrile with one extra carbon, and hydrolysing it gives a hydroxy acid — a two-step chain extension.
Connection to topic 17
The nitrile that is hydrolysed here can be made by adding HCN to an aldehyde or ketone (section 6). So the route aldehyde + HCN → hydroxynitrile → hydroxy acid builds the carbon chain by one, and produces a molecule with both an –OH and a –COOH. This is how the two topics connect.
(c) Hydrolysis of esters
An ester is hydrolysed by heating under reflux with dilute acid (reversible, catalysed by H+) or with dilute alkali (irreversible, because the acid is trapped as its carboxylate salt). Alkaline hydrolysis must be followed by acidification to obtain the free carboxylic acid.
CH3COOCH2CH3 + H2O ⇌ CH3COOH + CH3CH2OH (dilute acid, reflux)
CH3COOCH2CH3 + NaOH → CH3COO−Na+ + CH3CH2OH (dilute alkali, reflux)
Exam alert
Alkaline hydrolysis gives the salt of the acid (e.g. sodium ethanoate), not the acid itself. To obtain ethanoic acid, the mixture must be acidified with a strong acid, such as dilute HCl, afterwards.
Carboxylic acids as acids18.1.2
Carboxylic acids are weak acids. In water, ethanoic acid partially dissociates:
CH3COOH(aq) ⇌ CH3COO−(aq) + H+(aq)
The carboxylate ion, RCOO−, is stabilised by delocalisation: the negative charge is spread equally over the two oxygen atoms, making the ion less willing to take the proton back. Even so, the equilibrium lies well to the left — only about 1 in 250 ethanoic acid molecules is dissociated in a 1.0 mol dm−3 solution. Carboxylic acids are much weaker than mineral acids such as HCl.
Despite being weak, they are strong enough to react with metals, alkalis and carbonates. The five reactions below are all in outcome 18.1.2.
(a) Reaction with reactive metals
Carboxylic acids react with reactive metals such as magnesium or zinc. The acid donates H+, the metal is oxidised, a salt and hydrogen gas are produced. The reaction is slower and gentler than the same metals with hydrochloric acid.
2CH3COOH + Mg → (CH3COO)2Mg + H2(g)
ethanoic acid + magnesium → magnesium ethanoate + hydrogen
Observation: The metal dissolves and effervescence is seen (hydrogen). A lighted splint gives a squeaky pop.
(b) Neutralisation with alkalis
With a base such as NaOH or KOH, the reaction is a standard neutralisation: acid + base → salt + water.
CH3COOH + NaOH → CH3COONa + H2O
ethanoic acid + sodium hydroxide → sodium ethanoate + water
There is no visible change (unless an indicator is present), because both the acid and the salt are colourless solutions.
(c) Reaction with carbonates
Carboxylic acids react with carbonates (e.g. Na2CO3) and hydrogencarbonates (e.g. NaHCO3) to give a salt, water and carbon dioxide.
2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2(g)
CH3COOH + NaHCO3 → CH3COONa + H2O + CO2(g)
Observation: Effervescence (carbon dioxide). The gas turns limewater milky. This is a quick test to confirm that an unknown liquid is a carboxylic acid: add sodium carbonate or sodium hydrogencarbonate and look for fizzing.
Exam alert
The carbonate test distinguishes carboxylic acids from alcohols. Ethanol does not fizz with Na2CO3 — it is too weak an acid. A question that asks you to tell an alcohol from a carboxylic acid often expects this test.
(d) Esterification with alcohols
A carboxylic acid reacts with an alcohol, with concentrated H2SO4 as catalyst, to form an ester and water. The reaction is reversible and reaches equilibrium.
CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
ethanoic acid + ethanol ⇌ ethyl ethanoate + water
Heat under reflux. The concentrated sulfuric acid both catalyses the reaction (providing H+) and absorbs water, shifting the equilibrium to the right.
(e) Reduction by LiAlH4
LiAlH4 in dry ether reduces a carboxylic acid to a primary alcohol. NaBH4 is not strong enough.
CH3COOH + 4[H] → CH3CH2OH + H2O
ethanoic acid → ethanol
The product has the same number of carbon atoms. The –COOH carbon becomes the –CH2OH carbon of a primary alcohol.
Common trap
Reduction of a carboxylic acid needs 4[H], not 2[H]. Two [H] would give an aldehyde, but LiAlH4 does not stop there — it goes all the way to the alcohol. And the reducing agent must be LiAlH4; NaBH4 cannot reduce carboxylic acids.
How to think about it
The five reactions of carboxylic acids are the same reactions any acid shows, plus esterification (which is specific to organic acids) and reduction (which works on the C=O part of the molecule). The first three — metals, alkalis, carbonates — test the acidic hydrogen; esterification tests both the –OH and the C=O; reduction converts the C=O back to CH2.
Esters: formation by condensation18.2.1(a)
An ester is formed when a carboxylic acid reacts with an alcohol. The reaction is a condensation: two molecules join together and a small molecule — water — is lost. The link that forms between the acid and the alcohol is the ester linkage, –COO–.
Definition
An ester has the functional group –COO– (or –CO2–). It is named from the alcohol part first (as an alkyl group), then the acid part (with the ending changed from –ic acid to –ate). So ethanoic acid + ethanol gives ethyl ethanoate.
The esterification reaction
Heat a carboxylic acid with an alcohol and a few drops of concentrated H2SO4 as catalyst, under reflux. The reaction is reversible and reaches equilibrium.
CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
ethanoic acid + ethanol ⇌ ethyl ethanoate + water
CH3COOH + CH3OH ⇌ CH3COOCH3 + H2O
ethanoic acid + methanol ⇌ methyl ethanoate + water
CH3CH2COOH + CH3CH2OH ⇌ CH3CH2COOCH2CH3 + H2O
propanoic acid + ethanol ⇌ ethyl propanoate + water
The concentrated sulfuric acid serves two roles: it provides H+ ions that catalyse the reaction, and it absorbs water, shifting the equilibrium towards the ester.
Exam alert
Three things must appear in your answer: (1) heat under reflux, (2) concentrated H2SO4 as catalyst, (3) the reaction is reversible (show ⇌ in the equation). Omitting any one loses marks.
Naming esters
The name of an ester has two parts. The first part comes from the alcohol (the alkyl group): methyl from methanol, ethyl from ethanol, propyl from propan-1-ol. The second part comes from the acid, with –ic acid replaced by –ate: ethanoic acid becomes ethanoate, propanoic acid becomes propanoate.
| Acid | Alcohol | Ester | Name |
|---|---|---|---|
| ethanoic acid | methanol | CH3COOCH3 | methyl ethanoate |
| ethanoic acid | ethanol | CH3COOCH2CH3 | ethyl ethanoate |
| ethanoic acid | propan-1-ol | CH3COOCH2CH2CH3 | propyl ethanoate |
| propanoic acid | methanol | CH3CH2COOCH3 | methyl propanoate |
| propanoic acid | ethanol | CH3CH2COOCH2CH3 | ethyl propanoate |
Esters often have a sweet or fruity smell. In the lab, warming an acid with an alcohol and a drop of concentrated sulfuric acid and then pouring the mixture into water lets you smell the ester — it sits on top of the water as a thin, fragrant layer.
How to think about it
Esterification is the reverse of acid hydrolysis (section 6). The same equilibrium connects all four species — acid, alcohol, ester and water. Driving it one way (with concentrated H2SO4 and reflux) makes the ester; driving it the other way (with excess water and an acid catalyst, or with alkali) breaks the ester apart.
Hydrolysis of esters18.2.2
Hydrolysis is the breaking of a bond by water. In an ester, the bond that breaks is the C–O bond of the ester linkage, splitting the molecule back into the carboxylic acid (or its salt) and the alcohol. There are two methods.
Acid hydrolysis
Heat the ester under reflux with dilute hydrochloric acid (or dilute sulfuric acid). The H+ ions catalyse the reverse of esterification. This is a reversible reaction — it reaches equilibrium, so hydrolysis is not complete.
CH3COOCH2CH3 + H2O ⇌ CH3COOH + CH3CH2OH
ethyl ethanoate + water ⇌ ethanoic acid + ethanol
Alkaline hydrolysis (saponification)
Heat the ester under reflux with dilute sodium hydroxide (or potassium hydroxide). The hydroxide ion attacks the ester and the reaction goes to completion — it is irreversible, because the carboxylic acid produced is immediately neutralised to its carboxylate salt.
CH3COOCH2CH3 + NaOH → CH3COO−Na+ + CH3CH2OH
ethyl ethanoate + sodium hydroxide → sodium ethanoate + ethanol
To obtain the free carboxylic acid from alkaline hydrolysis, the solution must be acidified afterwards (e.g. with dilute HCl).
| Acid hydrolysis | Alkaline hydrolysis | |
|---|---|---|
| Reagent | dilute HCl (or dilute H2SO4) | dilute NaOH (or dilute KOH) |
| Conditions | heat under reflux | heat under reflux |
| Reversibility | reversible (equilibrium) | irreversible (goes to completion) |
| Organic products | carboxylic acid + alcohol | carboxylate salt + alcohol |
| To get the free acid | already produced | acidify the salt afterwards |
Exam alert
Alkaline hydrolysis gives the salt of the acid (e.g. sodium ethanoate), not the acid itself. To obtain ethanoic acid, the mixture must be acidified with a strong acid, such as dilute HCl, afterwards. A common error is to write the free acid as the direct product of alkaline hydrolysis.
Common trap
Students sometimes confuse acid hydrolysis with esterification in reverse. They are the same equilibrium, but the conditions differ: esterification uses concentrated H2SO4 (to absorb water and push equilibrium towards the ester), while acid hydrolysis uses dilute acid (excess water pushes the equilibrium towards the acid and alcohol).
Worked example
Propyl methanoate is heated under reflux with dilute NaOH. Name the organic products and write the equation.
Propyl methanoate has the propyl group from propan-1-ol and the methanoate group from methanoic acid. Alkaline hydrolysis gives:
HCOOCH2CH2CH3 + NaOH → HCOO−Na+ + CH3CH2CH2OH
Products: sodium methanoate and propan-1-ol.
Reaction map18.1, 18.2
The interactive map below connects the reactions of carboxylic acids. Pick a starting compound and a target to see the multi-step route with reagents and conditions for each step.
Data summary18.1, 18.2
| Conversion | Reagents and conditions |
|---|---|
| primary alcohol → carboxylic acid | acidified K2Cr2O7 or KMnO4, reflux, excess oxidant |
| aldehyde → carboxylic acid | acidified K2Cr2O7 or KMnO4, reflux |
| nitrile → carboxylic acid | dilute acid or dilute alkali (then acidify), reflux |
| ester → carboxylic acid + alcohol | dilute acid or dilute alkali (then acidify), reflux |
| carboxylic acid → primary alcohol | LiAlH4 in dry ether |
| carboxylic acid + alcohol → ester | concentrated H2SO4 catalyst, heat under reflux |
| carboxylic acid + metal | room temperature → salt + H2 |
| carboxylic acid + alkali | room temperature → salt + H2O |
| carboxylic acid + carbonate | room temperature → salt + H2O + CO2 |
| Test | Reagent | Positive result with | Observation |
|---|---|---|---|
| Carbonate test | Na2CO3(s) or NaHCO3(aq) | carboxylic acids | effervescence (CO2) |
Self-test18.1, 18.2
Twenty questions covering topics 18.1 and 18.2. Each question has one correct answer and an explanation. Reset to start again.